Write first $6$ terms of an $A . P .$ whose first term is $1$ and common difference $- 4$ .

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Solution

First term $= a = 1$
Common difference $= d = - 4$
Second term $= t_{2} = a + d = 1 - 4 = - 3$
Third term $= t_{3} = a + 2 d = 1 + 2 \times - 4 = 1 - 8 = - 7$
Fourth term $= t_{4} = a + 3 d = 1 + 3 \times - 4 = 1 - 12 = - 11$
Fifth term $= t_{5} = a + 4 d = 1 + 4 \times - 4 = 1 - 16 = - 15$
Sixth term $= t_{6} = a + 5 d = 1 + 5 \times - 4 = 1 - 20 = - 19$
$∴,$ the six terms of A.P are $1, - 3, - 7, - 11, - 15, - 19$

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