Write four rational numbers between x and additive inverse of x, where x = - $\frac{6}{11}$ .

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Solution

$x = \frac{- 6}{11}$ its additive inverse is $\frac{6}{11}$
rational numbers between $\frac{- 6}{11}$ and $\frac{6}{11}$
$\frac{- 5}{13}, \frac{5}{13}, \frac{- 3}{11}, \frac{3}{11}$

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Question 11
If x + 0 = 0 + x = x, which is rational number, then 0 is called:
(a) identity for addition of rational numbers.
(b) additive inverse of x.
(c) multiplicative inverse of x.
(d) reciprocal of x.

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Write four rational numbers between x and additive inverse of x, where x = - $\frac{6}{11}$ .

$x = \frac{- 6}{11}$ its additive inverse is $\frac{6}{11}$
rational numbers between $\frac{- 6}{11}$ and $\frac{6}{11}$
$\frac{- 5}{13}, \frac{5}{13}, \frac{- 3}{11}, \frac{3}{11}$