Question

Write four solutions[co-ordinates which satisfy the equation] for
$x+2y=3$

Answer 1

Equation is $x+2y=3$

(1) Let $x=1$

Substitute $x=1$ in the equation to find $y$

$1+2y=3$

$2y=3-1$

$2y=2$

$y=1$

So one solution is $(x,y)=(1,1)$

(2) Let $x=-1$

Substitute $x=-1$ in the equation to find $y$

$-1+2y=3$

$2y=3+1$

$2y=4$

$y=2$

So second solution is $(x,y)=(-1,2)$

(3) Let $x=0$

Substitute $x=0$ in the equation to find $y$

$0+2y=3$

$2y=3$

$y=\frac{3}{2}$

So third solution is $(x,y)=(0,\frac{3}{2})$

(4) Let $x=2$

Substitute $x=2$ in the equation to find $y$

$2+2y=3$

$2y=1$

$y=\frac{1}{2}$

So fourth solution is $(x,y)=(2,\frac{1}{2})$