Question

Write four solutions for each of the following equations:
$\left(i\right)2x+y=9$
$\left(ii\right)xy+y=9$
$\left(iii\right)x=4y$

Answer 1

1)$2x+y=9⟹y=9-2x$

$x=1$ then $y=9-2\left(1\right)=7$

$x=0$ then $y=9-2\left(0\right)=9$

$x=2$ then $y=9-2\left(2\right)=5$

$x=3$ then $y=9-2\left(3\right)=3$

$(0,9),(1,7),(2,5),(3,3)$ are four solutions

2)$xy+y=9⟹y=\frac{9}{x+1}$

$x=0$ then $y=\frac{9}{0+1}=9$

$x=1$ then $y=\frac{9}{1+1}=4.5$

$x=2$ then $y=\frac{9}{1+2}=3$

$x=8$ then $y=\frac{9}{1+8}=1$

$(0,9),(1,4.5),(2,3),(8,1)$ are four solutions

3)$x=4y$

$y=0$ then $x=0$

$y=1$ then $x=4$

$y=2$ then $x=8$

$y=3$ then $x=12$

$(0,0),(4,1),(8,2),(12,3)$ are four solutions