Write hydrocarbon radicals that can be formed as intermediate during monochlorinated of 2-methylpropane ? Which of them is more stable ? Give reasons .
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Solution
2-methylpropane gives two types of radicals: (1) CH3−CH(CH3)−∗CH2
(2) CH3−∗C(CH3)−CH3
Tertiary 3∘ free radical is more stable because it has 9α Hydrogen and Due to hyperconjugation structure is stabilized. Primary 1∘ free radical is less stable because of only 1α hydrogen, and one hyper conjugative structure.