Write in exponential form: $2^{3} + 2^{5} + 2^{6} - 2^{2}$

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Solution

$2^{3} + 2^{5} + 2^{6} - 2^{2}$

Take $2^{2}$ common

$\Rightarrow 2^{2} (2^{1} + 2^{3} + 2^{4} - 2^{0})$

$\Rightarrow 2^{2} (2 + 8 + 16 - 1)$

$\Rightarrow 2^{2} (25)$

$\Rightarrow 2^{2} \times 5^{2}$

Therefore, $\Rightarrow 2^{3} + 2^{5} + 2^{6} - 2^{2} = 2^{2} \times 5^{2}$

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