Question

Write is ascending order:

$3\sqrt{5}<4\sqrt{3}$
If true then enter$1$ and if false then enter $0$

Answer 1

We have,
$3\sqrt{5}=\sqrt{9\times 5}=\sqrt{45}$
$4\sqrt{3}=\sqrt{16\times 3}=\sqrt{48}$
Since $45<48;\sqrt{45}<\sqrt{48}$