Question

Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.

Answer 1

Mg: There are two valence electrons in Mg atom. Hence, the Lewis dot symbol for Mg is: $\stackrel{..}{Mg}$

Na: There is only one valence electron in an atom of sodium. Hence, the Lewis dot structure is: $N{a}^{.}$

B: There are 3 valence electrons in Boron atom. Hence, the Lewis dot structure is: $.\underset{.}{B}.$

O: There are six valence electrons in an atom of oxygen. Hence, the Lewis dot structure is: $\stackrel{..}{:O:}$

N: There are five valence electrons in an atom of nitrogen. Hence, the Lewis dot structure is: $\stackrel{..}{:N^{.}}$

Br: There are seven valence electrons in bromine. Hence, the Lewis dot structure is: $\underset{.}{\stackrel{..}{:Br:}}$