Question

Write $\log 48$ in terms of $\log 2$ and $\log 3$

Answer 1

We know that,

$\log 48=\log 16\times 3$

$=\log 16+\log 3$ using $\log \left(ab\right)=\log a+\log b$

$=\log 2^4+\log 3$

$=4\log 2+\log 3$ using $\log a^m=m\log a$