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Question

Write minors and cofactors of elements of following determinants

∣ ∣100010001∣ ∣

∣ ∣104351012∣ ∣

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Solution

Here,

∣ ∣100010001∣ ∣
Minors of elements of first row are
M11=1001=10=1, M12=0001=00=0

and M13=0100=00=0
Minors of elements of second row are
M21=0001=00=0M22=1001=10=1 and M23=1000=00=0
Minors of elements of third row are
M31=0010=00=0M32=1000=00=0 and M33=1001=10=1

Hence, cofactors of elements of first row are
A11=(1)1+1M11=1×1=1,A12=(1)1+2M12=1×0=0A13=(1)1+3M13=1×0=0

cofactors of elements of second row are
A21=(1)2+1M21=1×0=0,A22=(1)2+2M22=1×1=1A23=(1)2+3M23=1×0=0


Coafactors of elements of third row are
A31=(1)3+1M31=1×0=0,A32=(1)3+2M32=1×0=0A33=(1)3+3M33=1×1=1

Here,
∣ ∣104351012∣ ∣
Minors of elements of first row are
M11=5112=10+1=11,M12=3102=60=6 and M13=3501=30=3
Minors of elements of second row are
M21=0412=04=4M22=1402=20=2 and M23=1001=10=1
Minors of elements of third row are
M31=0451=020=20M32=1431=112=13 and M33=1035=50=5

Hence, cofactors of elements of first row are
A11=(1)1+1M11=1×11=11,A12=(1)1+2M12=1×6=6A13=(1)1+3M13=1×3=3
cofactors of elements of second row are
A21=(1)2+1M21=1×4=4,A22=(1)2+2M22=1×2=2A23=(1)2+3M23=1×1=1
Coafactors of elements of third row are
A31=(1)3+1M31=1×20=20,A32=(1)3+2M32=1×13=13A33=(1)3+3M33=1×5=5


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