Question

Write reactions of the final alkylation product of aniline with an excess of methyl iodide in the presence of sodium carbonate solution.

Answer 1

Step 1: Alkylation of aniline

Aniline reacts with methyl iodide to produce N, N-dimethylaniline.

Part 2: Reaction of the alkylated product of aniline with an excess methyl iodide

When N, N-dimethylaniline reacts with excess methyl iodide in the presence of $N{a}_{2}C{O}_3$ solution, leading to the production of N, N, N−trimethylaniliniumcarbonate.