Write structures of compounds A and B in each of the following reaction:

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Solution

Aniline reacts with concentrated sulphuric acid to form anilinium hydrogensulphate which on heating with sulphuric acid at $453 - 473 K$ produces $p$ -aminobenzene sulphonic acid, commonly known as sulphanilic acid, as the major product.
$C_{6} H_{5} - N H_{2} Conc. H_{2} S O_{4} - ------ \to {C_{6} H_{5} N H_{3}}^{+} {H S O_{4}}^{-} (Anilinium hydrogen sulphate) heat 453 - 473 K - --------- \to S O_{3} H - C_{6} H_{4} - N H_{2} (p-aminobenzene sulphonic acid)$
Hence the compound $A$ is anilinium hydrogen sulphate and the compound $B$ is $p$ -aminobenzene sulphonic acid.

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A, B

Write the structures of compounds A, B and C in the following reactions:

$C_{6} H_{5} {N O}_{2} F e / H C l - ---- \to A H {N O}_{2}; 273 K - ------ \to B C_{6} H_{5} O H - ---- \to C$

(i)

Write Lewis structure of the following compound and show formal charge on each atom.

$H N O_{3}$

(ii)

Write Lewis structure of the following compound and show formal charge on each atom.

$N O_{2}$

(iii)

Write Lewis structure of the following compound and show formal charge on each atom.

$H_{2} S O_{4}$

^{'} A^{'},^{'} B^{'},^{'} C^{'}

^{'} D^{'}

^{'} A^{'} + C H_{3} M g B r H_{2} O - - \to C H_{3} C H_{2} C H (O H) C H_{3} c o n c . H_{2} S O_{4} - ------ \to^{'} B^{'} B r_{2} - - \to^{'} C^{'} a l c . K O H - ---- \to^{'} D^{'}

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