Question

Write structures of the products of the following reactions:

A
B
C

Answer 1

Alkenes react with $H_{2}O/H^{+}$ to give alcohols. The product is formed according to Markovnikov’s rule. This is known as hydration of alkenes.

When propene reacts with $H_{2}O/H^{+}$ (hydration reaction) then the product formed is- Propan-$2$-ol .




$NaB{H}_4$ is a reducing agent. $NaB{H}_4$ is less reactive than $LiAl{H}_4$ but is otherwise similar.
It is only powerful enough to
reduce aldehydes, ketones and acid chlorides to alcohols. Esters, amides, acids and nitriles does not get reduced by it.

In the given compound, the functional groups are ketone and ester. $NaB{H}_4$ will reduce ketone group only to alcohol.
It can be given as -



$NaB{H}_4$ is a reducing agent. $NaB{H}_4$ is less reactive than $LiAl{H}_4$ but is otherwise similar.
It is only powerful enough to
reduce aldehydes, ketones and acid chlorides to alcohols. Esters, amides, acids and nitriles does not get reduced by it.

In the given compound, the functional group is aldehyde. $NaB{H}_4$ will reduce aldehyde group to alcohol. It can be given as –