Write 'T' for true and 'F' for false
(i) In −x, the constant term is −1.
(ii) The coefficient of x in x2−3x+5 is 3.
(iii) (5x−7)−(3x−5)=2x−12.
(iv) (3x+5y)(3x−5y)=(9x2−25y2).
(v) If a=2 and b=12, then the value of ab(a2+b2) is 414.
(i)
Given polynomial function −x=−x+0.
So, the constant term is 0.
Thus, the constant term is −1 is false.
Therefore, the given statement is false (F).
(ii)
Given polynomial x2−3x+5
The coefficient of x is −3.
So, the coefficient of x is 3 is false.
Therefore, the given statement is false(F).
(iii)
Given equation (5x−7)−(3x−5)=2x−12.
LHS=(5x−7)−(3x−5)
=5x(3x−5)+7(3x−5)
=15x2−25x+21x−35
=15x2−4x−35
≠ RHS
Therefore, the given statement is false(F).
(iv)
Given (3x+5y)(3x−5y)=(9x2−25y2)
LHS=(3x+5y)(3x−5y)
=3x(3x−5y)+5y(3x−5y)
=9x2−15xy+15xy−25y2
=9x2−25y2
=RHS.
Therefore, the given statement is true(T).
(v)
If a=2 and b=12, then the value of ab(a2+b2) is 414.
ab(a2+b2)
=2(12)(22+(12)2)
=24(4+144)
=24(148)
=3552
Therefore, the given statement is False (F).