Question

Write $\tan \theta$ in terms of $\sin \theta$.

Answer 1

We have $\tan \theta =\frac{\sin \theta }{\cos \theta }$

As we know $\cos \theta =\sqrt{1-{\sin }^2\theta }$

$⟹\tan \theta =\frac{\sin \theta }{\sqrt{1-{\sin }^2\theta }}$