Question

Write the additive inverse of $-\frac{19}{6}$ and $-\frac{2}{3}$.

Answer 1

Additive inverse.

An additive inverse of a given number is, a number when added to a given number yields zero.

Let $n$is a number, then additive inverse will be $-n$ because $n+(-n)=0$.

Therefore,

The additive inverse of $-\frac{19}{6}$ will be $\frac{19}{6}$because $-\frac{19}{6}+\frac{19}{6}=0$.

The additive inverse of $-\frac{2}{3}$ will be $\frac{2}{3}$because $-\frac{2}{3}+\frac{2}{3}=0$.

Hence, the additive inverse of $-\frac{19}{6}$ and $-\frac{2}{3}$ are $\frac{19}{6}$ and $\frac{2}{3}$respectively.