Question

Write the additive inverse of $\frac{5}{8}$

Answer 1

Finding the additive inverse of $\frac{5}{8}$:

For each each non-zero integer $a$, there is an integer $-a$ such that

$a+\left(-a\right)=\left(-a\right)+a=0$

Where $-a$ is called additive inverse of $a$

Let us assume that $a=\frac{5}{8}$

$\Rightarrow \frac{5}{8}+(-a)=0$

$\Rightarrow -a=-\frac{5}{8}$

Therefore, the additive inverse of $\frac{5}{8}$ is $-\frac{5}{8}$.