Write the algebraic expressions for
Seven times the reciprocal of a number added to $\frac{1}{8} t h$ times the other number.

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Solution

Finding the solutions
Let the no be $X$
According to question
The reciprocal of a number means $\frac{1}{X}$
And Seven times the reciprocal of a number = $7 \times \frac{1}{X}$
Also $\frac{1}{8} t h$ times the other number = $\frac{1}{8} \times Y$
Now, Seven times the reciprocal of a number added to $\frac{1}{8} t h$ times the other number = $7 \times \frac{1}{X}$ $+$ $\frac{1}{8} \times Y$
Hence Seven times the reciprocal of a number added to $\frac{1}{8} t h$ times the other number = $7 \times \frac{1}{X}$ $+$ $\frac{1}{8} \times Y$

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