Write the answer in both Hindu Arabic and Roman system- M - CCL - MCCXI - CDXLV III

Step 1: M = 1000 CCL = 250 MCC × 1 = 1211 CDXLVIII = 448 Step 2: 1000 ÷ 250 + 1211 448 = 4 + 1211 448 = 1215 448 = 767 Step 3: 767 = 700 + 60 + 7 =DCC L ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard V

Mathematics

Roman Numerals

Write the ans...

Question

Write the answer in both Hindu Arabic and Roman system.
$M \div C C L + M C C X I - C D X L V I I I$

Open in App

Solution

Step 1:
M = 1000
CCL = 250
$M C C \times 1 = 1211$
CDXLVIII = 448
Step 2:
$1000 \div 250 + 1211 - 448$
= 4 + 1211 - 448
= 1215 - 448
= 767
Step 3: 767
= 700 + 60 + 7
=DCC LX VII

Suggest Corrections

Similar questions

Q. The Roman numeral M represents in the Hindu Arabic numeral.

Q. Write 86324805 separating periods in HIndu-Arabic system.

L X X X I

= _______ (Write the value in Hindu - Arabic number,)

Q. Pair the Roman numerals with their Hindu-Arabic counterparts.

Q. Write the following numbers in Hindu-Arabic system.
(i)

1256345

(ii)

12027896

Join BYJU'S Learning Program

Write the answer in both Hindu Arabic and Roman system. M÷CCL+MCCXI−CDXLVIII

Step 1: M = 1000 CCL = 250 MCC×1=1211 CDXLVIII = 448 Step 2: 1000÷250+1211−448 = 4 + 1211 - 448 = 1215 - 448 = 767 Step 3: 767 = 700 + 60 + 7 =DCC LX VII

Write the answer in both Hindu Arabic and Roman system.
$M \div C C L + M C C X I - C D X L V I I I$

Step 1:
M = 1000
CCL = 250
$M C C \times 1 = 1211$
CDXLVIII = 448
Step 2:
$1000 \div 250 + 1211 - 448$
= 4 + 1211 - 448
= 1215 - 448
= 767
Step 3: 767
= 700 + 60 + 7
=DCC LX VII