Write the answer in standard form
$(- 2 - 3 i) - (- 9 + 9 i) - (2 + 5 i)$

9 - 7 i

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5 + 11 i

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5 - 17 i

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- 9 + 11 i

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Solution

The correct option is C $5 - 17 i$
$(- 2 - 3 i) - (- 9 + 9 i) - (2 + 5 i)$
= $- 2 - 3 i + 9 - 9 i - 2 - 5 i$
= $- 2 + 9 - 2 - 3 i - 9 i - 5 i$
= $5 - 17 i$

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Imaginary part of third element of the second row for the Conjugate of $⎡ ⎢ ⎣ \begin{matrix} 3 + 4 i & 4 & 2 + 5 i 1 + 2 i & 2 + 3 i & 3 + 5 i 2 + 7 i & 9 & 5 \end{matrix} ⎤ ⎥ ⎦$ is

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Q. If

| z - 5 - 7 i | = 9,

then find the greatest and least values of

| z - 2 - 3 i | .

Q. Assertion :

40 + 9 i > 12 + 5 i

where

\sqrt{- 1} = i

. Reason:

40 > 12

9 > 5

Q. Find the product and write the answer in standard form.

(2 - 4 i) (3 + 7 i)

Q. Prove that the value of the determinant

∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} - 7 & 5 + 3 i & \frac{2}{3} - 4 i 5 - 3 i & 8 & 4 + 5 i \frac{2}{3} + 4 i & 4 - 5 i & 9 \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣

is real.

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Write the answer in standard form(−2−3i)−(−9+9i)−(2+5i)

The correct option is C 5−17i(−2−3i)−(−9+9i)−(2+5i)= −2−3i+9−9i−2−5i= −2+9−2−3i−9i−5i= 5−17i

Write the answer in standard form
$(- 2 - 3 i) - (- 9 + 9 i) - (2 + 5 i)$

The correct option is C $5 - 17 i$
$(- 2 - 3 i) - (- 9 + 9 i) - (2 + 5 i)$
= $- 2 - 3 i + 9 - 9 i - 2 - 5 i$
= $- 2 + 9 - 2 - 3 i - 9 i - 5 i$
= $5 - 17 i$