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Formula for Sum of n Terms of an AP

Write the AP ...

Question

Write the AP whose $n^{t h}$ term is given by $a_{n} = 9 - 5 n .$

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Solution

$a_{n} = 9 - 5 n a_{0} = 9 - 5 \times 0 = 9 a_{1} = 9 - 5 \times 1 = 4 a_{2} = (9 - 5 \times 2) = - 1 a_{3} = (9 - 5 \times 3) = - 6 a_{4} = (9 - 5 \times 4) = - 11$
AP is as follow
$9, 4, - 1, - 6, - 11, . . .$
With
$a_{0} = 9 d = - 5$

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