Question

Write the balanced chemical equation for the following reaction:

Copper chloride using Copper carbonate.

Answer 1

Formation of Copper chloride:

• Hydrochloric acid decomposes the carbonate into the respective chloride along with the evolution of carbon dioxide.
• Copper carbonate $\left({\mathrm{CuCO}}_3\right)$ reacts with Hydrochloric acid $\left(\mathrm{HCl}\right)$ to give Copper (II) chloride $\mathbf{\left(}{\mathbf{CuCl}}_{\mathbf{2}}\mathbf{\right)}$, water, and Carbon dioxide gas$\left({\mathrm{CO}}_2\right)$ as a product.

Balanced chemical equation:

$\underset{\mathrm{Copper}\mathrm{carbonate}}{{\mathrm{CuCO}}_3\left(\mathrm{s}\right)}+\underset{\mathrm{Hydrochloric}\mathrm{acid}}{2\mathrm{HCl}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Copper}\left(\mathrm{II}\right)\mathrm{chloride}}{{\mathrm{CuCl}}_2\left(\mathrm{aq}\right)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}+\underset{\mathrm{Carbon}\mathrm{dioxide}}{{\mathrm{CO}}_2\left(\mathrm{g}\right)}$