Question

Write the balanced chemical equation for the following

Sodium ethonate to methane

Answer 1

• When sodium ethanoate react with sodium hydroxide, methane and sodium carbonate is formed.
• Here carboxyl group is removed from sodium ethanoate. So it is a decarboxylation reaction.
• $\underset{\mathrm{sodiumethanoate}}{{\mathrm{CH}}_3\mathrm{COONa}\left(\mathrm{aq}\right)}+\underset{\mathrm{soda}\mathrm{lime}}{\underbrace{\mathrm{CaO}+\underset{}{\mathrm{NaOH}\left(\mathrm{aq}\right)}}}\stackrel{∆}{\to }\underset{\mathrm{methane}}{{\mathrm{CH}}_4\left(\mathrm{g}\right)}+\underset{\mathrm{sodium}\mathrm{carbonate}}{{\mathrm{Na}}_2{\mathrm{CO}}_3\left(\mathrm{aq}\right)}$