Write the balanced chemical equation for the last step of oxidation test of sulphur.

B a C l_{2} + N a_{2} S O_{4} ⟶ B a S O_{4} + 2 N a C l

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H C l + N a_{2} S O_{4} ⟶ N a H S O_{4} + N a C l

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B a C l_{2} + 2 H C l ⟶ 2 C l_{2} + B a + H_{2}

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None of the above

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Solution

The correct option is A $B a C l_{2} + N a_{2} S O_{4} ⟶ B a S O_{4} + 2 N a C l$
The presence of sulphur in the organic compound can be detected by the following tests:
Oxidation Test:
The organic compound is fused with a mixture of potassium nitrate and sodium carbonate. Sulphur, if present, gets oxidised to sodium sulphate.
$3 K N O_{3} ⟶ 3 K N O_{2} + 3 [O] {N a}_{2} C O_{3} + S + 3 [O] ⟶ {N a}_{2} S O_{4} + C O_{2}$
The fused mass is extracted with water, the contents are boiled and filtered. The filtrate contains sodium sulphate. The filtrate is acidified with dilute hydrochloric acid and a solution of barium chloride is added. Formation of a white precipitate indicates the presence of sulphur.
$B a {C l}_{2} + {N a}_{2} S O_{4} ⟶ B a S O_{4} ↓ + 2 N a C l$

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Similar questions

Balance the following chemical equations.

(a)

(b)

(c)

(d)

N a_{2} S O_{4} + B a C l_{2} \to B a S O_{4} + 2 N a C l

1.	Column-A Types of chemical reaction		Column-B Chemical equation
(A)	Combination reaction	(i)	$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$
(B)	Oxidation & reduction reaction	(ii)	$2 H_{2} O E l e c t r i c i t y ⟶ 2 H_{2} + O_{2}$
(C)	Decomposition reaction	(iii)	$C a O + C O_{2} \to C a C O_{3}$
(D)	Displacement reaction	(iv)	$H_{2} + C l_{2} \to 2 H C l$
(E)	Double Displacement reaction	(v)	$B a C l_{2} + N a_{2} S O_{4} \to B a S O_{4} ↓ + N a C l$

B a C l_{2} + N a_{2} S O_{4} \to B a S O_{4} + 2 N a C l

H {N O}_{3} + C a {(O H)}_{2} \to C a {({N O}_{3})}_{2} + H_{2} O

N a C l + A g {N O}_{3} \to A g C l + N a {N O}_{3}

B a {C l}_{2} + H_{2} {S O}_{4} \to B a {S O}_{4} + H C l

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