Question

Write the balanced chemical equations for the given reactions: Copper sulphate on treatment with potassium iodide precipitates cuprous iodide$\left({\mathrm{Cu}}_2{\mathrm{I}}_2\right)$, liberates iodine gas and forms potassium sulphate.

Answer 1

Balanced chemical equation: A balanced chemical equation is the representation of a chemical reaction in which the number of atoms of each element is the same on both the reactant and product sides.

Reaction of Copper sulphate with Potassium iodide:

• When the cuprous sulphate $\left({\mathrm{CuSO}}_4\right)$ reacts with potassium iodide $\left(\mathrm{KI}\right)$, cuprous iodide $\left({\mathrm{Cu}}_2{\mathrm{I}}_2\right)$ gets precipitated along with the liberation of iodine gas $\left({\mathrm{I}}_2\right)$, and potassium sulfate$\left({\mathrm{K}}_2{\mathrm{SO}}_4\right)$ is also formed as a product at the end of the reaction.
• The cuprous iodide so formed is a white-colored precipitate.
• The chemical reaction can be depicted as:

$2{\mathrm{CuSO}}_4\left(\mathrm{aq}\right)+4\mathrm{KI}\left(\mathrm{aq}\right)\to \underset{\mathrm{White}\mathrm{powder}}{{\mathrm{Cu}}_2{\mathrm{I}}_2\left(\mathrm{s}\right)}+2{\mathrm{K}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)+{\mathrm{I}}_2\left(\mathrm{g}\right)$