Write the balanced equation for the following reaction:

Sodium hydroxide reacts with calcium bromide to form calcium hydroxide and sodium bromide.

$2 N a O H + C a B r_{2} \to C a (O H)_{2} + 2 N a B r$

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$N a O H + C a B r_{2} \to C a (O H)_{2} + N a B r$

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$N a O H + C a B r \to C a (O H)_{2} + 2 N a B r$

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$2 N a O H + C a B r_{2} \to C a (O H)_{2} + N a B r_{2}$

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Solution

The correct option is A
$2 N a O H + C a B r_{2} \to C a (O H)_{2} + 2 N a B r$

The chemical equation for the following reaction will be:

Sodium hydroxide + Calcium bromide $⟶$ Calcium hydroxide + Sodium bromide.

Sodium hydroxide - $N a O H$ , Calcium bromide - $C a B r_{2}$ , Calcium hydroxide - $C a (O H)_{2}$ , Sodium bromide - $N a B r$

So the equation will be written as:
$N a O H + C a B r_{2} \to C a (O H)_{2} + N a B r$
Now to balance the equation we have to count the number of atoms on each side.

Number of Oxygen atoms on LHS - 1, Number of Oxygen atoms on RHS - 2
So we will multiply 2 on the reactant side to NaOH. So it will become;
$2 N a O H + C a B r_{2} \to C a (O H)_{2} + N a B r$

Number of Na atoms on the reactant side: 2; Number of Na atoms on the product side: 1
So we will multiply 2 on the product side to NaBr. So it will become;
$2 N a O H + C a B r_{2} \to C a (O H)_{2} + 2 N a B r$

Number of Hydrogen atoms on LHS - 2, Number of Hydrogen atoms on RHS - 2
Number of Calcium atoms on LHS - 1, Number of Calcium atoms on RHS - 1
Number of Bromine atoms on LHS - 2, Number of Bromine atoms on RHS - 2

Hence the equation is balanced.
$2 N a O H + C a B r_{2} \to C a (O H)_{2} + 2 N a B r$

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Similar questions

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$2 N a O H + C a B r_{2} \to C a (O H)_{2} + 2 N a B r$

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Write the balanced equation for the following reaction: Sodium hydroxide reacts with calcium bromide to form calcium hydroxide and sodium bromide.

Write the balanced equation for the following reaction:

Sodium hydroxide reacts with calcium bromide to form calcium hydroxide and sodium bromide.