Write the cell reaction and calculate the e.m.f. of cell for $C l_{2} (1 a t m) | N a C l (a q) | C l_{2} (0.1 a t m)$ . Will the cell reaction be spontaneous?

-0.0295, Non-spontaneous

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-0.0295, spontaneous

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0.0295, Non-spontaneous

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0.0295, spontaneous

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Solution

The correct option is A -0.0295, Non-spontaneous
$C l_{2} (1 a t m) | N a C l (a q) | C l_{2} (0.1 a t m)$
as we know,
$E = 0.059 / 2 l o g (0.1 / 1) = - 0.0295$
as E< 0 so its a non-spontaneous reaction.

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