Question

Write the chemical equation for each of the following:

Oxidation of ethanol by ${\mathrm{KMnO}}_4$.

Answer 1

In the compound, Ethanol $\left({\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\right)$ indicates the alcohol functional group present in the compound.

In an organic reaction, the reagent reacts with a reactant molecule to produce an intermediate which is converted into final products.

The reaction of Ethanol with alkaline Potassium permanganate $\left({\mathrm{KMnO}}_4\right)$ solution forms an oxidized product.

The reaction of Ethanol with alkaline Potassium permanganate solution forms Ethanoic acid $\left({\mathrm{CH}}_3\mathrm{COOH}\right)$ as the major product.

The chemical equation of the reaction is written as:

$$\begin{gathered} {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\stackrel{\mathrm{alk}.{\mathrm{KMnO}}_4}{\to }{\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{H}}_2\mathrm{O} \\ \left(\mathrm{Ethanol}\right)(\mathrm{Ethanoic}\mathrm{acid})\left(\mathrm{Water}\right) \end{gathered}$$