Write the chemical equation for the preparation of phosphoric acid $(H_{3} P O_{4})$ from orthophosphorus acid $(H_{3} P O_{3})$ ?

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Solution

$H_{3} P O_{3}$ is orthophosphorous acid. It is more clearly described with the structural formula $H P O {(O H)}_{2}$ . This acid is diprotic, i.e., it readily ionizes two protons.It is an unstable compound that readily absorbs moisture, it is converted to phosphoric acid ( $H_{3} P O_{4}$ ) in the presence of oxygen or when heated above $180^{0} C (360 F)$ .
$H_{3} P O_{3} + \frac{1}{2} O_{2} ⇌ H_{3} P O_{4}$

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