Question

Write the chemical name for the ionic compound ${\mathbf{PbCrO}}_{\mathbf{4}}$ and mention its molecular weight in brackets after the name.

Answer 1

${\mathbf{PbCrO}}_{\mathbf{4}}$ :

• The chemical name of ${\mathbf{PbCrO}}_{\mathbf{4}}$ is lead (II) chromate.
• This ionic compound exists as a vivid yellow colored powder and it is insoluble in general.
• It is composed of lead, chromium, and oxygen with molecular weights of 207.2, 51.9961 and 16 gm/mol respectively. Hence the molecular weight of ${\mathbf{PbCrO}}_{\mathbf{4}}$ is 323.1961 gm/mol [207.2+51.9961+(16*4)].

Thus, the chemical name and molecular weight for the ionic compound ${\mathbf{PbCrO}}_{\mathbf{4}}$ is lead (II) chromate (323.1961 gm/mol).