CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Write the coefficient of xn in the expansion of eabx.

Open in App
Solution

eabx=eaebx=ea(1+(bx)1!+(bx)22!+(bx)33!+............)
Hence coefficient of xn is given by ea(b)nn!.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon