Question

Write the complement angle of:
(iv) ${20}^o+y^o$

Answer 1

Step 1:Finding the complementary angle of ${20}^o+y^o$
We know that ,two angles are said to be
complementary if their sum is ${90}^o$
Let the complement angle of$({20}^o+y^o)$ be $x$
$\therefore ({20}^o+y^o)$+x=${90}^o$
$x={90}^o-({20}^o+y^o)$
$x={90}^o-{20}^o+y^o$
$\therefore x=(70-y^0)$
Hence,complement angle $({20}^o+y^o)$ is $x=(70-y^0)$