Write the complement of-i aii x - 5oiii 13rd of 180o

(i) The complement of a = 90^o a (ii) The complement of nbsp; (x + 5)^o = 90^o (x + 5)^o = 85^o x^o (iii) The complement of 13 rd of 180^o = 90^o 13 rd ...

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Standard IX

Mathematics

Adjacent Angles

Write the com...

Question

Write the complement of:
(i) $a$
(ii) $(x + 5)^{o}$
(iii) $\frac{1}{3}$ rd of $180^{o}$

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Solution

(i) The complement of $a = 90^{o} - a$
(ii) The complement of $(x + 5)^{o} = 90^{o} - (x + 5)^{o} = 85^{o} - x^{o}$
(iii) The complement of $\frac{1}{3}$ rd of $180^{o} =$
$90^{o} - \frac{1}{3}$ rd of $180^{o} = 90^{o} - 60^{o} = 30^{o}$

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Write the complement of: (i) a (ii) (x+5)o (iii) 13rd of 180o

(i) The complement of a=90o−a (ii) The complement of (x+5)o=90o−(x+5)o=85o−xo (iii) The complement of 13 rd of 180o= 90o−13 rd of 180o=90o−60o=30o

Write the complement of:
(i) $a$
(ii) $(x + 5)^{o}$
(iii) $\frac{1}{3}$ rd of $180^{o}$

(i) The complement of $a = 90^{o} - a$
(ii) The complement of $(x + 5)^{o} = 90^{o} - (x + 5)^{o} = 85^{o} - x^{o}$
(iii) The complement of $\frac{1}{3}$ rd of $180^{o} =$
$90^{o} - \frac{1}{3}$ rd of $180^{o} = 90^{o} - 60^{o} = 30^{o}$