Write the conditions to maximize the yield of $H_{2} S O_{4}$ by contact process?

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Solution

The main step in the preparation of $H_{2} S O_{4}$ is the oxidation of $S O_{2}$ to $S O_{3}$ .
$2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}; △ H_{f}^{\circ} = - 196.6 k J / m o l^{- 1}$ .

The reaction is exothermic and reversible. The forward reaction proceeds with decrease in volume.

Therefore according to Le Chatelier's principle, to maximise the yield of $S O_{3}$ , a low temperature $(720 K)$ , a high pressure $(2 b a r)$ are required. $V_{2} O_{5}$ is used as a catalyst.

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