Question

Write the conjugate of $\sqrt{3}i-7$

Answer 1

For any complex number $a+bi$ the complex conjugate is $a-bi$, i.e.,

The real term remains unchanged, while the imaginary term becomes the negative of its value.

Therefore,

Conjugate of $\sqrt{3}i-7=-\sqrt{3}i-7=-(\sqrt{3}i+7)$