Question

Write the coordinates of the point where line $3x+4y=12$ intersects $Y-$axis.

Answer 1

$3x+4y=12$ intersect y-axis

$3x+4y=12$ [Divide with 12 on both sides]

$\frac{3}{12}x+\frac{4}{12}y=\frac{12}{12}$

$\frac{1}{4}x+\frac{1}{3}y=1$

$\therefore$ The coordinates of the point

on y-axis $(0,3)$.