Write the correct information in the space provided.
$\begin{matrix} s . n o . & C h e m i c a l r e a c t i o n & S u b s t a n e o x i d i s e d & S u b s t a n c e r e d u c e d & O x i d i s i n g a g e n t & R e d u c i n g a g e n t 1. & 2 H_{2} S + S O_{2} \to 2 H_{2} O + 3 S 2. & Z n O + C \to Z n + C O \end{matrix}$

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Solution

S in $S O_{2}$ is reduced and S in $H_{2} S$ is oxidized.
Reduction is a gain of electrons. (more negative)
Oxidation is a loss of electrons (becoming more positive)
Since oxygen has combined with carbon is the one that is oxidized and ZnO is the oxidizing agent. Similarly carbon has taken the oxygen of ZnO, carbon id the reducing agent and ZnO is the one that has been reduced.
Reducing agent - C
Oxidizing agent - ZnO
Oxidized - C
Reduced - ZnO

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Similar questions

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Z n O + C \to Z n + C O

which substance gets oxidised and which gets reduced?

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$Z n O + C \to Z n + C O$

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Write the correct information in the space provided. s.no.Chemical reactionSubstane oxidisedSubstance reducedOxidising agentReducing agent1.2H2S+SO2→2H2O+3S2.ZnO+C→Zn+CO