Write the cube root of 27125.
On prime factorisation of the numbers individually, we get,
27=3×3×3––––––––––=33.
125=5×5×5––––––––––=53.
Therefore, cube root of 27125 is:
3√27125=3√3353=35.
Therefore, option A is correct.
The expanded form of (3x−5)3 is(a) 27x3+135x2+225x−125(b) 27x3+135x2−225x−125(c) 27x3−135x2+225x−125(d) none of these
Solve:
[[5×{(−3)×(−4)}]÷{27 + (−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}] +[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)] +[{(−3)×(−3)×5}÷(−3)]]