Write the dimension of $a$ & $b$ the eq $v = a t + b$ ; where, $^{'} v^{'}$ is velocity an $^{'} t^{'}$ is time.

Open in App

Solution

Given $v = a t + b$ $\Rightarrow$ Dimension of $v = [L T^{- 1}]$
Dimension of $a t = [L T^{- 1}]$ $\Rightarrow$ Dimension of $a = [L T^{- 2}]$
$\Rightarrow$ Dimension of $b = [L T^{- 1}]$

Suggest Corrections

Similar questions

Write the dimensions of the a and b in the equation v=a+bt where v is velocity and t is time

Q. The velocity v of a point at time t is given by

v = a t + \frac{b}{t + c}

. The dimension of a, b and c are respectively:

Q. If

v = \frac{a}{t} + b t^{3}

where

v =

velocity and

t

is time. The dimensional formula of

a

and

b

are

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

, where

a, b

and

c

are constant. The dimensions of

a, b

and

c

are respectively.

The velocity $v$ of a particle at time $t$ is given by $v = a t + \frac{b}{t + c}$ where $a, b$ and $c$ are constants. The dimensions of $a, b$ and $c$ are respectively :

Join BYJU'S Learning Program

Write the dimension of a & b the eq v=at+b; where, ′v′ is velocity an ′t′ is time.

Given v=at+b ⇒ Dimension of v=[LT−1]Dimension of at=[LT−1] ⇒ Dimension of a=[LT−2]⇒ Dimension of b=[LT−1]

Write the dimension of $a$ & $b$ the eq $v = a t + b$ ; where, $^{'} v^{'}$ is velocity an $^{'} t^{'}$ is time.

Given $v = a t + b$ $\Rightarrow$ Dimension of $v = [L T^{- 1}]$
Dimension of $a t = [L T^{- 1}]$ $\Rightarrow$ Dimension of $a = [L T^{- 2}]$
$\Rightarrow$ Dimension of $b = [L T^{- 1}]$