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Question

Write the dimensions of a × b in the relation E=bx2at, where E is the energy, x is the displacement and t is time.


A

ML2T

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B

M1L2T1

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C

MLT2

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D

ML2T2

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Solution

The correct option is B

M1L2T1


Here [b] and [x]2=L2 have same dimensions.

Also [a]=[x]2[E]×[t] =L2(ML2T2)T =M1T1

a×b=[M1L2T1]

hence correct answer is (b).


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