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Question

Write the direction ratio's of the vector a=^i+^j2^k and hence calculate its direction cosines.

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Solution

a=^i+^j2^k

|a|=1+1+4=6
Directioncosines=(axa,aya,aza)ie(16,16,16)
Direction ratio = (1,1,-2)

1173369_1347115_ans_33f5a8d6a1b249bf933f9019553cc846.jpg

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