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Question

Write the distance of the plane r·2i^-j^+2k^=12 from the origin.

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Solution

The given equation of the plane isr. 2 i^- j^+2 k^ = 12 or r. n = -6, where n = 2 i ^- j^ + 2 k^n = 4+1+4 = 3For reducing the given equation to normal form, we need to divide both sides by n. Then, we getr. nn=12nr. 2 i^- j^+2 k^3 = 123r. 23 i^-13 j^+23k^ = 4 ... 1The equation of the plane in normal form isr. n^ = d ... 2(where d is the distance of the plane from the origin)Comparing (1) and (2),length of the perpendicular from the origin to the plane = d = 4 units

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