Question

Write the electron dot structure for the following compound: ${\mathrm{O}}_2$.

Answer 1

Electron dot structure

• A Lewis electron dot structure, also known as an electron dot structure, is a representation of an atom's valence electrons that uses dots $\left(:\right)$ around the element's symbol.
• The number of dots in the diagram represents the number of valence electrons in the atom.
• These dots are put to the right and left of the symbol, as well as above and below it, with no more than two dots on each side.
• Covalent bonds between atoms can be represented by dots $\left(:\right)$ or dashes $\left(-\right)$.

Electron dot structure for ${\mathbf{O}}_{\mathbf{2}}$:

• On the periodic table, Oxygen $\left(\mathrm{O}\right)$ belongs to group $16$.
• The atomic number of Oxygen is $8$.
• The electronic configuration is as follows:

$\mathrm{O}=1s^{2}2s^{2}2p^4$

• As a result, the valence electron in oxygen is $6$.
• The given molecule ${\mathrm{O}}_2$ is diatomic oxygen.
• In the ${\mathrm{O}}_2$ molecule, there are $12$ valence electrons.
• ${\mathrm{O}}_2$ molecule undergoes covalent bonding between two oxygen atoms in order to fulfill its octet. There are 2 pairs of non-bonded electrons on each oxygen atom in the molecule.
• The electron dot structure is as follows: