Write the electronic configuration of ${}_{11}A$ .Find out A is a metal, non metal or inert gas.

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Solution

The atomic number of A is given as 11. The atomic number is the number of protons in an atom. It will thus have 11 protons.
In an electrically neutral atom, number of protons will be equal to number of electrons.Hence A will have 11 electrons.
Electronic configuration of A will be :- 2,8,1.
A has only one electron in its valence shell and it can lose this electron to attain octet configuration.
Therefore A is a metal which is sodium (Na).

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