Write the electronic configuration of ${}_{3}E$ .Find out E is a metal, non metal or inert gas.

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Solution

Given the atomic number of E is 3.
Atomic number is the number of protons in an atom. In an electrically neutral atom, number of electrons and protons will be same.
Thus E will have 3 electrons and hence the electronic configuration: 2,1.
Since E is having only one electron in the valence shell, it will lose this electron and attain nearest noble gas configuration.
The nearest noble gas is helium with 2 electrons and the electronic configuration:2.
Thus E will be a metal .
Metals will have 1 to 3 valence electrons.

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