Write the electronic configuration of Oxygen, Chlorine and Sodium according to the Bohr-Bury Scheme.[3 MARKS]

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Solution

Each configuration: 1 Mark

Atomic Number of O = 8, Electrons in K shell = 2, Electrons in L shell = 6. Configuration = 2, 6
Atomic Number of Cl = 17, Electrons in K shell = 2, Electrons in L shell = 8, Electrons in M shell = 7. Configuration = 2, 8, 7
Atomic Number of Na = 11, Electrons in K shell = 2, Electrons in L shell = 8, Electrons in M shell = 1. Configuration = 2, 8, 1

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