Write the electronic configuration of the following elements
(a) Sulphur (Z = 16)
(b) Krypton (Z = 36)

Open in App

Solution

The electronic configuration is as given below.
(a) Sulphur (Z = 16) :
it belongs to group 16 (VIA) and third period. Its electronic configuration is
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$
(b) Krypton (Z = 36) :
It belongs to group 18 (zero group) and fourth period. It is a noble gas. Its electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6}$

Suggest Corrections

Similar questions

Q. Krypton (Atomic number

36

) has the electronic configuration

[A r] 4 s^{2} 3 d^{10} 4 p^{6}

. The

37

th electron will go into which one of the following sub-levels?

(a) Write down the electronic configuration of (i) magnesium atom, and (ii) magnesium ion.
(At. No. of Mg = 12 )
(b) Write down the electronic configuration of (i) sulphur atom and (ii) sulphur ion.
(At. No. of S = 16)

Q. Write the valency numbers of following elements-Magnesium, Silicon, Krypton and Sulphur

Q. Which of the following ions has the same number of electrons as a krypton atom with atomic number

36

Q. Out of ozone, phosphorus, sulphur and krypton, the elements having the lowest and highest atomicities are respectively :
(a) sulphur and krypton
(b) krypton and ozone
(c) phosphorus and sulphur
(d) krypton and sulphur

Join BYJU'S Learning Program

Write the electronic configuration of the following elements(a) Sulphur (Z = 16)(b) Krypton (Z = 36)

Write the electronic configuration of the following elements
(a) Sulphur (Z = 16)
(b) Krypton (Z = 36)