Question

Write the element $a_{21}$ of the matrix $A=[a_{ij}{]}_{2\times 2}$ whose elements $a_{ij}$ are given by $a_{aj}=e^{2ix}\cos jx$

Answer 1

Solution:-

Given that:-

$a_{ij}=e^{2ix}\cos jx$

To find:- $a_{21}=?$

For $a_{21}$,

$i=2$

$j=1$

$\therefore a_{21}=e^{(2\times 2\times x)}\cos (1\times x)=e^{4x}\cos x$