Question

Write the equation for the laboratory preparation of ethane from sodium propionate.

Answer 1

Laboratory preparation of ethane from sodium propionate

• Sodium Propionate (${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{COONa}$) reacts with Sodium hydroxide ($NaOH$) and forms Ethane ($C_2{H}_6$) and Sodium carbonate ($N{a}_{2}C{O}_3$) as the products.
• The equation for the preparation of Ethane from Sodium propionate is as follows:

$\underset{\mathrm{Sodium}\mathrm{Propionate}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{COONa}\left(\mathrm{s}\right)}+\underset{\mathrm{Sodium}\mathrm{hydroxide}}{\mathrm{NaOH}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Ethane}}{{\mathrm{C}}_2{\mathrm{H}}_6\left(\mathrm{g}\right)}+\underset{\mathrm{Sodium}\mathrm{carbonate}}{{\mathrm{Na}}_2{\mathrm{CO}}_3\left(\mathrm{aq}\right)}$