Write the equation for the reaction of zinc with hydrochloric acid and balance the equation. Find out the number of molecules of hydrogen gas produced in this reaction, when $1$ mole of $H C l$ completely reacts at S.T.P

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Solution

When Zinc reacts with hydrochloric acid the following reaction takes place:
$Z n + 2 H C l \to Z n C l_{2} + H_{2 (g)} ↑$
Here 1 molecules of hydrochloric acid taking part in the reaction,the number of molecules of hydrogen produced in the reaction.
$4 m o l e s o f H C l \times \frac{1 m o l e o f H_{2}}{2 m o l e s o f H C l} = 2 m o l e s o f H_{2}$

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Write the equation for the reaction of zinc with hydrochloric acid and balance the equation. Find out the number of molecules of hydrogen gas produced in this reaction, when 1 mole of HCl completely reacts at S.T.P

When Zinc reacts with hydrochloric acid the following reaction takes place:Zn+2HCl→ZnCl2+H2(g)↑Here 1 molecules of hydrochloric acid taking part in the reaction,the number of molecules of hydrogen produced in the reaction. 4molesofHCl×1moleofH22molesofHCl=2molesofH2

Write the equation for the reaction of zinc with hydrochloric acid and balance the equation. Find out the number of molecules of hydrogen gas produced in this reaction, when $1$ mole of $H C l$ completely reacts at S.T.P